Pembuktian Rumus Limit Fungsi Trigonometri (sinx/x)

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Published on Oct 03, 2024 This response is partially generated with the help of AI. It may contain inaccuracies.

Table of Contents

Introduction

This tutorial will guide you through the process of proving the limit of the trigonometric function sin(x)/x as x approaches 0. Understanding this limit is fundamental in calculus, particularly in the study of derivatives and integrals of trigonometric functions. It serves as a building block for more complex mathematical theories and applications.

Step 1: Understand the Limit Concept

  • Begin by grasping what it means to find the limit of a function as it approaches a specific value.
  • The limit of sin(x)/x as x approaches 0 is a classic example in calculus that often requires a geometric interpretation and algebraic manipulation.

Step 2: Visualize the Function

  • Draw the unit circle and locate the angle x (in radians).
  • Identify the following components:
    • The length of the arc corresponding to angle x (which is x).
    • The vertical line segment representing sin(x).
    • The tangent line at the point (1,0) which intersects the vertical line.

This visualization helps to understand why the limit approaches 1.

Step 3: Establish the Squeeze Theorem

  • Use the Squeeze Theorem to prove the limit:
    • Show that for x in the interval (0, π/2), the following inequalities hold:
      • sin(x) < x < tan(x)
    • Recognize that tan(x) can be expressed as sin(x)/cos(x).

From these inequalities, you can derive the following:

  • sin(x)/x < 1 < 1/cos(x)

Step 4: Take the Limit

  • As x approaches 0, apply the inequalities:
    • The limit of sin(x)/x as x approaches 0 is squeezed between two bounds converging to 1.

Formally, you can express this as:

  • lim (x -> 0) sin(x)/x = 1

Step 5: Verify with the Derivative

  • You can also verify this limit using L'Hôpital's Rule, which applies to indeterminate forms like 0/0.
  • Differentiate the numerator and denominator:
    • The derivative of sin(x) is cos(x).
    • The derivative of x is 1.

Thus, applying L'Hôpital's Rule gives:

lim (x -> 0) sin(x)/x = lim (x -> 0) cos(x)/1 = cos(0) = 1

Conclusion

In this tutorial, you learned how to prove that lim (x -> 0) sin(x)/x = 1 using geometric visualization, the Squeeze Theorem, and L'Hôpital's Rule. Understanding this limit is essential in calculus and has numerous applications in higher mathematics. As a next step, practice applying these concepts to other trigonometric limits and explore their implications in calculus further.