Turunan Aturan Rantai Trigonometri - Rumus Cepat

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Published on Jan 05, 2025 This response is partially generated with the help of AI. It may contain inaccuracies.

Table of Contents

Introduction

This tutorial focuses on the chain rule for derivatives in trigonometry, providing a quick and efficient way to understand and apply this important concept. The chain rule is a fundamental technique in calculus that allows you to differentiate composite functions, which is especially useful when dealing with trigonometric functions.

Step 1: Understanding the Chain Rule Concept

  • The chain rule states that if you have a composite function, say ( h(x) = f(g(x)) ), the derivative ( h'(x) ) can be expressed as:

    [ h'(x) = f'(g(x)) \cdot g'(x) ]

  • Here’s what each part represents:

    • ( f ) is the outer function.
    • ( g ) is the inner function.
    • ( f' ) is the derivative of the outer function evaluated at the inner function ( g(x) ).
    • ( g' ) is the derivative of the inner function.

Practical Tip

  • Always identify the inner and outer functions first when applying the chain rule.

Step 2: Applying the Chain Rule to Trigonometric Functions

  1. Identify the outer and inner functions in your trigonometric expression.

    • Example: For ( h(x) = \sin(x^2) ):
      • Outer function: ( f(u) = \sin(u) )
      • Inner function: ( g(x) = x^2 )
  2. Differentiate both functions:

    • Derivative of the outer function: ( f'(u) = \cos(u) )
    • Derivative of the inner function: ( g'(x) = 2x )
  3. Apply the chain rule:

    • Substitute ( g(x) ) back into the derivative of the outer function:

    [ h'(x) = \cos(g(x)) \cdot g'(x) = \cos(x^2) \cdot (2x) ]

  4. Final result:

    [ h'(x) = 2x \cos(x^2) ]

Common Pitfall

  • Forgetting to differentiate both the inner and outer functions can lead to incorrect results.

Step 3: Examples of Chain Rule with Different Trigonometric Functions

  • Example 1: Differentiate ( h(x) = \tan(3x + 1) )

    • Outer function: ( f(u) = \tan(u) )
    • Inner function: ( g(x) = 3x + 1 )
    • Derivative:

    [ h'(x) = \sec^2(3x + 1) \cdot 3 = 3 \sec^2(3x + 1) ]

  • Example 2: Differentiate ( h(x) = \cos(x^3) )

    • Outer function: ( f(u) = \cos(u) )
    • Inner function: ( g(x) = x^3 )
    • Derivative:

    [ h'(x) = -\sin(x^3) \cdot 3x^2 = -3x^2 \sin(x^3) ]

Conclusion

The chain rule is essential for differentiating composite trigonometric functions. By identifying the outer and inner functions and applying the rule correctly, you can easily find derivatives for a wide range of expressions. As you practice more examples, the process will become more intuitive. For further study, consider exploring higher-order derivatives and their applications in real-world problems.